Question

factorise 3b² - b - 10​

Answer 1

Answer:

The first term is,  3b2  its coefficient is  3 .

The middle term is,  +b  its coefficient is  1 .

The last term, "the constant", is  -10  

Step-1 : Multiply the coefficient of the first term by the constant   3 • -10 = -30  

Step-2 : Find two factors of  -30  whose sum equals the coefficient of the middle term, which is   1 .

     -30    +    1    =    -29  

     -15    +    2    =    -13  

     -10    +    3    =    -7  

     -6    +    5    =    -1  

     -5    +    6    =    1  

Step-by-step explanation:

Answer 2

Answer:

(3b+5)(b-2)

Step-by-step explanation:

3b^2-b-10

3b^2-6b + 5b-10

3b(b-2) + 5(b-2)

(3b+5) (b-2)