Math, asked by HarshaR2607, 1 year ago

Factorise 4a square -9B square -16 C Square +24BC

Answers

Answered by sudhakara7470
0

Answer:

4a²-9b²-16c²+24bc

16a²+81b²+256c²

Answered by ashishks1912
2

The factorised expression to the given expression is =(2a)^2-(3B-4C)^2

4a^2-9B^2-16C^2+24BC=(2a)^2-(3B-4C)^2

Step-by-step explanation:

Given expression is 4a^2-9B^2-16C^2+24BC

To factorise the given expression :

  • 4a^2-9B^2-16C^2+24BC=2^2a^2-3^2B^2-4^2C^2+24BC
  • =(2a)^2-(3B)^2-(4C)^2+24BC ( rewritting the terms to simplify )
  • =(2a)^2-(3B)^2-(4C)^2+2(3B)(4C)
  • =(2a)^2-[(3B)^2+(4C)^2-2(3B)(4C)]
  • =(2a)^2-(3B-4C)^2  ( using the identity a^2+b^2-2ab=(a-b)^2 here a=3B and b=4C )

4a^2-9B^2-16C^2+24BC=(2a)^2-(3B-4C)^2

The factorised expression to the given expression is =(2a)^2-(3B-4C)^2

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