Question

Factorise: 〖4y〗^2 – 8y + 3.​

Answer 1

Answer:

${4y}^{2} - 8y + 3 \\ = {(2y)}^{2} - 2y - 6y + 3 \\ = 2y(2y - 1) - 3(2y - 1) \\ = (2y - 1)(2y - 3)$

Answer 2

Step-by-step explanation:

4y^2-8y+3

=(2y)^2-2y-6y+3

=2y(2y-1)-3(2y-1)

=(2y-1)(2y-3)

hope this helps you mate ✨