Question

factorise:(5a+2/3)^2-(2a-1/3)^2

Answer 1

hope this will help you.

Answer 2

Answer:

$(5a+\frac{2}{3})^{2}-(2a-\frac{1}{3})^{2}\\=(7a+\frac{1}{3})(3a+1)$

Step-by-step explanation:

$Given \:(5a+\frac{2}{3})^{2}-(2a-\frac{1}{3})^{2}\\=[\:(5a+\frac{2}{3})+(2a-\frac{1}{3})][\:(5a+\frac{2}{3})-(2a-\frac{1}{3})]$

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By algebraic identity:

$\boxed {x^{2}-y^{2}=(x+y)(x-y)}$

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$= (5a+\frac{2}{3}+2a-\frac{1}{3})(5a+\frac{2}{3}-2a+\frac{1}{3})$

$=(7a+\frac{1}{3})(3a+\frac{3}{3})$

$=(7a+\frac{1}{3})(3a+1)$

Therefore,

$(5a+\frac{2}{3})^{2}-(2a-\frac{1}{3})^{2}\\=(7a+\frac{1}{3})(3a+1)$

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