Question

factorise: 64a^3-16a^2+4/3a-1/27​

Answer 1

Answer:

$64 {a}^{3} - 16 {a}^{2} + \frac{4}{3} a - \frac{1}{27} \\ = {(4a)}^{3} - 3\times \frac{1}{3} {(4a)}^{2} + 3 \times 4a \times { \frac{1}{3} }^{2} - {( \frac{1}{3}) }^{3} \\ = {(4a - \frac{1}{3} )}^{3} \\ = (4a - \frac{1}{3} )(4a - \frac{1}{3} )(4a - \frac{1}{3} )$