Question

factorise 6x^3-7x^2-11x+12​

Answer 1

$\bold{\huge{\fbox{\color{Maroon}{♡Hello♡}}}}$

=> (((6 • (x3)) - 7x2) - 11x) + 12

=> (((2•3x3) - 7x2) - 11x) + 12

=>6x3-7x2-11x+12 is not a perfect cube

=>Factoring: 6x3-7x2-11x+12

=>Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -11x+12

Group 2: 6x3-7x2

=>Pull out from each group separately :

Group 1: (-11x+12) • (1) = (11x-12) • (-1)

Group 2: (6x-7) • (x2)

=>Final result :

$\bold{\small{\fbox{\color{Black}{(x - 1)(3x + 4)(2x - 3)}}}}$

$\bold{\huge{\fbox{\color{Pink}{♡Thanks♡}}}}$

Answer 2

$\bold{Answer}$=> (((6 • (x3)) - 7x2) - 11x) + 12

=> (((2•3x3) - 7x2) - 11x) + 12

=>6x3-7x2-11x+12 is not a perfect cube

=>Factoring: 6x3-7x2-11x+12

=>Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -11x+12

Group 2: 6x3-7x2

=>Pull out from each group separately :

Group 1: (-11x+12) • (1) = (11x-12) • (-1)

Group 2: (6x-7) • (x2)

=>Final result :

(x−1)(3x+4)(2x−3)