Question

factorise: 6xy( a^2+b^2)+8yz(a^2+b^2)-10​

Answer 1

$\huge\underline{\mathbb\red{❥︎A}\green{N}\mathbb\blue{S}\purple{W}\mathbb\orange{E}\pink{R}}\:$

6xy(a2 + b2) + 8yz(a2 + b2) - 10xz(a2 + b2) H.C.F. of 6, 8, 10 = 2, then 2(a2 + b2) (3xy + 4yz - 5xz)

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Answer 2

6xy(a2 + b2) + 8yz(a2 + b2) - 10xz(a2 + b2) H.C.F. of 6, 8, 10 = 2, then 2(a2 + b2) (3xy + 4yz - 5xz)