factorise 729x^3-512y^3
Answers
Answered by
141
hi friend!!
729x³-512y³
=(9x)³-(8y)³
we know that a³-b³=(a-b)(a²+b²+ab)
→(9x-8y)(81x²+64y²+72xy)
therefore, (9x-8y) and (81x²+64y²+72xy) are the factors.
I hope this will help u ;)
729x³-512y³
=(9x)³-(8y)³
we know that a³-b³=(a-b)(a²+b²+ab)
→(9x-8y)(81x²+64y²+72xy)
therefore, (9x-8y) and (81x²+64y²+72xy) are the factors.
I hope this will help u ;)
Answered by
44
Hi,
Here is your answer !
_____________________________
729x³ - 512y³
= 9³x³ - 8³y³
= (9x)³ - (8y)³
= (9x - 8y) [ (9x)² + (8y)² + (9x)×(8y) ]
= (9x - 8y) ( 81x² + 64y² + 72xy )
================================
Identity used :
(a³ - b³) = (a - b) (a² + b² + ab)
Here is your answer !
_____________________________
729x³ - 512y³
= 9³x³ - 8³y³
= (9x)³ - (8y)³
= (9x - 8y) [ (9x)² + (8y)² + (9x)×(8y) ]
= (9x - 8y) ( 81x² + 64y² + 72xy )
================================
Identity used :
(a³ - b³) = (a - b) (a² + b² + ab)
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