Question

Factorise 75psquare qcube ×(25psquare-81qsquare)÷15pq×(5p+9q)

Answer 1

Answer:

$\red {\frac{75p^{2}q^{3} \times (25p^{2}-81q^{2}}{15pq\times (5p+9q)}} \green { = 5pq^{2} (5p-9q)}$

Step-by-step explanation:

$\frac{75p^{2}q^{3} \times (25p^{2}-81q^{2}}{15pq\times (5p+9q)}\\= \frac{15pq \times 5pq^{2} \times [(5p)^{2}-(9q)^{2}]}{15pq\times (5p+9q)}\\= \frac{ 5pq^{2} \times (5p+9q)(5p-9q)}{(5p+9q)}\\= 5pq^{2} (5p-9q)$

Therefore.,

$\red {\frac{75p^{2}q^{3} \times (25p^{2}-81q^{2}}{15pq\times (5p+9q)}} \green { = 5pq^{2} (5p-9q)}$

•••♪