Question

factorise 8 a cube + root 27 b cube

Answer 1

Hey here is your answer
I HOPE IT WILL HELP YOU
This time it was ryt ok
using formula
x3+y3 =(x+y)(x2-xy+y2)
understand

Answer 2

Answer:

$8a^{3}+\sqrt{27}b^{3}</p><p>=(2a+\sqrt{3}b)[4a^{2}-2\sqrt{3}ab+3b^{2}]$

Step-by-step explanation:

$8a^{3}+\sqrt{27}b^{3}$

$=(2a)^{3}+(\sqrt{3}b)^{3}$

$=(2a+\sqrt{3}b)[(2a)^{2}-(2a)(\sqrt{3}b)+(\sqrt{3}b)^{2}]$

/* By algebraic identity:

$\boxed {x^{3}+y^{3}=(x+y)(x^{2}-xy+y^{2}}$*/

$=(2a+\sqrt{3}b)[4a^{2}-2\sqrt{3}ab+3b^{2}]$

Therefore,

$8a^{3}+\sqrt{27}b^{3}</p><p>=(2a+\sqrt{3}b)[4a^{2}-2\sqrt{3}ab+3b^{2}]$

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