Question

factorise- 8a cube+√(27b cube)

Answer 1

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Answer 2

Ans.

$8 {a}^{3} + 27 {b}^{3} \\ = {(2a})^{3} + {(3b)}^{3} \\ = (2a + 3b)(4 {a}^{2} - 6ab + 9 {b}^{2} )$

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