factorise 8x cube + b cube +12a square* b + 6ab square
Answers
Answered by
464
Hi ,
**************************************
We know the algebraic identity
x³ + y³ + 3x²y + 3xy² = ( x + y )³
****************************************
Now ,
8a³ + b³ + 12a²b + 6ab²
= ( 2a )³ + b³ + 3 × ( 2a )² b + 3×(2a)b²
= ( 2a + b )³
= ( 2a + b )( 2a + b )( 2a + b )
( 2a + b ) , ( 2a + b ) , ( 2a + b ) are
factors.
I hope this helps you.
:)
**************************************
We know the algebraic identity
x³ + y³ + 3x²y + 3xy² = ( x + y )³
****************************************
Now ,
8a³ + b³ + 12a²b + 6ab²
= ( 2a )³ + b³ + 3 × ( 2a )² b + 3×(2a)b²
= ( 2a + b )³
= ( 2a + b )( 2a + b )( 2a + b )
( 2a + b ) , ( 2a + b ) , ( 2a + b ) are
factors.
I hope this helps you.
:)
Answered by
176
HELLO
8x³ + b³ + 12a²b + 6ab²
= ( 2x )³ + ( b)³ + 3.2x².b + 3.2x.b
= ( 2x + b )³
= ( 2x + b ) ( 2x + b ) ( 2x + b )
note: used ( a + b )³ = a³ + 3a²b + 3ab² + b³ formula
thanks you
8x³ + b³ + 12a²b + 6ab²
= ( 2x )³ + ( b)³ + 3.2x².b + 3.2x.b
= ( 2x + b )³
= ( 2x + b ) ( 2x + b ) ( 2x + b )
note: used ( a + b )³ = a³ + 3a²b + 3ab² + b³ formula
thanks you
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