Question

Factorise 9a^2-4 (b-c)^2

Answer 1

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Here is your answer
$9 {a}^{2} - 4(b - c) {}^{2} \\ \\ = (3a) {}^{2} -( 2b - 2c) {}^{2} \\ \\ = (3a + (2b - 2c))(3a - (2b - 2c)) \\ \\ = (3a + 2b - 2c)(3a - 2b + 2c)$

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Answer 2

ANSWER IS

$(3a) {}^{2} - (2(b - c)) {}^{2} \\ = (3a) {}^{2} - (2b - 2c) {}^{2} \\ = (3a + 2b - 2c)(3a - 2b + 2c)$
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