factorise
9x4-(x2+2x+1)
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Answer:
9x^4-(x^2+2x+1)
⇒ 9x^4- ( x^2+2x+1 )
⇒ 9x^4- (x+1) (x+1)
⇒ 9x^4-(x+1)^2
[ in the form of a^2-b^2=(a+b)(a-b) ]
⇒ (3x^2)^2-(x+1)^2
⇒ [(3x^2-(x+1)] [(3x^2+(x+1)]
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