Question

Factorise: 9z2−x2+4xy−4y2
please answer quick I need it soon

Answer 1

$9z {}^{2} - x {}^{2} + 4xy - 4 {y}^{2}$

$= 9z {}^{2} (x {}^{2} - 4xy {}^{2} + 4y {}^{2} )$

$= 9z {}^{2} - (x {}^{2} - 2 \times x \times 2y + (2y) {}^{2} ))$

$= (3z) {}^{2} - (x - 2y) {}^{2}$

$(3x -( x + 2y))(3z + (x - 2y))$

$= (3z - x + 2y)(3z + x - 2y)$

$= (x - 2y + 3x)( - x + 2y + 3z)$

i think so my answer is helpful for you

Answer 2

Answer:

may month....... ....