Math, asked by gurpreet111119, 1 year ago

factorise a^2+b^2+2ab+2bc+2ca

Answers

Answered by BhawnaAggarwalBT
12
here is your answer

ANSWER:-
 {a}^{2}  +  {b}^{2}  + 2ab + 2bc + 2ca \\ (  {a}^{2}  +  {b}^{2}  + 2ab + 2bc + 2ca) +  {c}^{2}  -  {c}^{2}  \\ using \: identity \:  \\ {a}^{2} +   {b}^{2}  +  {c}^{2}  + 2ab + 2bc + 2ca \:  \\  = ( {a + b + c)}^{2}  \\  \\  = ( {a + b + c)}^{2}  -  {c}^{2}  \\   = (a  + b + c + c)(a + b + c - c) \\ =  (a + b  + 2c)(a + b)

thus is your full answer
hope this helps you

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