factorise :(a-2b)^3 +a +2b
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1-2a -2b -3(a+b)²
= 1-2(a+b)-3(a+b)²
=1- 3(a+b) +(a+b) -3(a+b)²
=1[1-3(a+b)]+(a+b)[1-3(a+b)]
=[1-3(a+b)][1+(a+b)]
=(1-3a-3b)(1+a+b)
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