Question

Two coins are tossed simultaneously 500 times ,and we get .

Two heads => 105 times.
One heads => 275 times.
No heads =>120 times.

No silly ans required ...

Answer 1

$\textbf{Now \:we \:have \:to \:denote \:event\: of \:getting \:two \:heads ,\:one \:head\: and \:no \:heads \:by \:E1 ,\:E2,\:E3 \:respectively .}$

weex]\underline\textbf{Formula\:used}[/tex] :- Number of heads / total number of tosses .

= > $\dfrac{105}{500}$

Ans. = > 0.21

$\dfrac{275}{500}$

Ans.= >0.55

$\dfrac{120}{500}$

Ans.= > 0.24

Answer 2

two head - 105/500

21/100

one heads - 275/500

11/20

no head - 120/500

6/25