Question

factorise (b-c)³ + (c-d)³ 3 + (d-b)³​

Answer 1

Answer:

= (b-c)^3 + (c-d)^3 + (b-d)^3

= b^3-c^3+ 3c^3-3d^3+d^3-b^3

= b^3-b^3+3c^3-c^3-3d^3+d^3

= 2c^3-2d^3

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