When zinc reacts with dilute nitric acid, nitrous oxide is produced. What is the mass of the gas is evolved by treating 325 g zinc with excess of nitric acid?
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Zinc reacts with dilute nitric acid producing N2O in accordance with the following equation. 4Zn + 10HNO3 = 4Zn(NO3)2 +N2O+5H2O. The atomic mass of Zn is 65.38u and the molecular weight of N2O is 44. So 65.38×4 g or 261.52 g of Zn gives 44 g of N2O.
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