Question

factorise
b) p^3(q-r)^3 +q^3(r-p) ^3+r^3(p-q) ^3​ maths

Answer 1

Answer:

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Answer 2

p³(q-r)³ + q³(r-p)³ + r³(p-q)³

=(p(q-r))³ +(q(r-p))³ + (r(p-q))³

a³ + b³ + c³ = (a + b + c)³ - 3 (a +b) (b + c) (a+ c)

= {p(q-r)+q(r-p)+r(p-q)}³ - 3[p(q-r)+q(r-p)][q(r-p)+r(p-q)]

[r(p-q)+p(q-r)]

= (pq-pr+qr-qp+rp-rq)³-3[pq-pr+qr-qp][qr-qp+rp-rq][rp-rq+pq-pr]

= 0³- 3[-pr+qr][-qp+rp][-rq+pq]

........

sry after this I don't know