Math, asked by soumodeepbaner71, 3 months ago

Mona’s father is thrice as old as Mona. After 12 years he will be just twice his
daughter. Find their present ages.

Answers

Answered by pankajjain000
0

Answer:

mona-12

father- 36

12+12=24

36+12=48

Answered by jyotimotorola678
1

Answer:

Let mono's age be x

then, her father's age is 3*

After 12 years:

2(x + 12 = 3x + 12

2*+ 243 *+12

3x-2x = 24-12 = 12

Mona's age = 12

Father's age - 3*= 12*3 = 36

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