factorise by middle term and by factor theorem
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6x2+9x-4x+6
3x[2x+3] -2[2x+3]
[2x+3] [3x-2]
3x[2x+3] -2[2x+3]
[2x+3] [3x-2]
Answered by
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6x2+9x-4x+6
3x[2x+3] -2[2x+3]
[2x+3] [3x-2]
I hope this would help u
3x[2x+3] -2[2x+3]
[2x+3] [3x-2]
I hope this would help u
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