Question

factorise by splitting the midfle term 2m^2 - 10m - 12

Answer 1

hey mate here is your answer ✌♥✌

2m²-10m-12

so

by splitting the middle term

2m²-12m+2m-12

2m(m-6)+2(m-6)

(m-6)(2m+2)

so the roots will be

m={6,-1}

hope it will help you

mark me brainliest ✌✌✌

Answer 2

$\huge \mathfrak {hii \: mate}$

$\huge \mathbb {HERE \: IS \: YOUR \: ANSWER}$

$2 {m}^{2} - 10m - 12 = 0 \\ = > 2 {m}^{2} - (12 - 2) m- 12 = 0 \\ = > 2 {m}^{2} - 12m \: + 2m - 12 = 0 \\ = > 2m(m - 6) + 2(m - 6) = 0$
$= > (2m + 2)(m - 6) = 0$

$2m + 2 = 0 \\ = > 2m \: = - 2 \\ = > m \: = \frac{ - 2}{2} \\ = > m = - 1$

$m - 6 = 0 \\ = > m = 6$

$\huge{Answer \: = \: -1 \: and \: 6}$

$\huge{verification}$

$a = 2 \\ b = - 1 \\ c = - 12 \\ \\ \\ \\ \\ sum \: of \: the \: zeroes = \frac{ - b}{a} \\ = > - 1 + 6 = \frac{ - ( - 10)}{2} \\ = > 5 = \frac{10}{2 } \\ = > 5 = 5 \\ \\ product \: of \: the \: zeroes = \frac{c}{a} \\ = > - 1 \times 6 = \frac{ - 12}{2} \\ \\ = > - 6 = - 6 \\ \\ \\ \huge{verified}$