Math, asked by shrimmakani23june, 1 month ago

factorise by using suitable identities 2z²-8​

Answers

Answered by malaytrivedi12345
0

Answer:

(z+2)(2z-4)

Step-by-step explanation:

2z²-0z-8

2z²+4z-4z-8

2z(z+2)-4(z+2)

(z+2)(2z-4)

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