Question

Factorise.
Hey Anyone please solve it .

Answer 1

Heya ✋

Let see your answer !!!

$8ab ^{2} - 18a ^{3} \\ = 2a(4b^{2} - 9a ^{2}) \\ = 2a((2b) ^{2} - (3a) ^{2}) \\ = 2a(2b + 3a)(2b - 3a)$


Thanks :)))))

Answer 2

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= 8 ab^2 - 18 a ^ 3

= 2 a( 4 b^2 - 9 a ^ 2 )

= - 2a ( 9 a^2 - 4 b^2 ) { By taking ( - ) common }

= -2a { ( 3 a )^2 - ( 2 b ) ^ 2 }  [ a^2 - b^2 = ( a + b ) ( a - b )]

= - 2a ( 3a + 2b ) ( 3a - 2b )

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