Factorise it :
Y^2+y+6
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Step-by-step explanation:
y^2+y+6
using discriminant
D=b^2-4ac
D=1-4(6)
D=-23
Since D is getting negative and so √D will be indefinable
There are no real roots
[I have one thing to say that may be either y or 6 any of these two must be having negative sign so then it may be solved easily]
By the way thanks for question.
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