factorise msquare +5x+6
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So equation can be written in the form of (x+a)*(x+b)
Where (x+a),(x+b) are factors of the equation.
So by expanding we get x^2+(a+b)x+ab.
By comparing the above equation with the given equation we get a+b=5, ab= 6
We know that (a-b)^2=(a+b)^2–4ab
So we get (a-b)^2=(5)^2–4(6)
(a-b)^2=25–24
(a-b)^2=1
(a-b)=+1 or -1
So a-b=+1 or -1
So a+b=5 and let a-b=1
Adding both equations we get 2a=6
So a=3 and substituting a in the above one of the equation we get b=2
Similarly by taking a-b=-1we get
a=2 and b=3
So the factors of the given equation are
(x+2) and (x+3)
this answer is related to your question
Where (x+a),(x+b) are factors of the equation.
So by expanding we get x^2+(a+b)x+ab.
By comparing the above equation with the given equation we get a+b=5, ab= 6
We know that (a-b)^2=(a+b)^2–4ab
So we get (a-b)^2=(5)^2–4(6)
(a-b)^2=25–24
(a-b)^2=1
(a-b)=+1 or -1
So a-b=+1 or -1
So a+b=5 and let a-b=1
Adding both equations we get 2a=6
So a=3 and substituting a in the above one of the equation we get b=2
Similarly by taking a-b=-1we get
a=2 and b=3
So the factors of the given equation are
(x+2) and (x+3)
this answer is related to your question
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