Question

factorise of a2(b-c)-b2(c-a)2

Answer 1

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Step  1  :

Equation at the end of step  1  :

((a2)•(b-c))-(b2•(c-a)•2)

Step  2  :

Equation at the end of step  2  :

((a2) • (b - c)) - 2b2 • (c - a)

Step  3  :

Equation at the end of step  3  :

a2 • (b - c) - 2b2 • (c - a)

Step  4  :

Final result :

a2b - a2c + 2ab2 - 2b2c

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