Question

Factorise:
${p}^{2} - 10q - 21 \\ {p}^{2} - 6p - 16$
​

Answer 1

Answer:

the above is 2 nd question answer

Step-by-step explanation:

${p}^{2} - 10q - 21$

$21 \: can \: be \: written \: as \: - 7 \times - 3$

hence

${p}^{2} - 7p - 3p - 21$

$take \: p \: common$

$p(1p - 7) - 3 \times (1p - 7)$

$(p - 3) \times (1p - 7)$

$p \: = 3 \: or \: p = 7$

this is 1 st question answer

hope it helps you

make me as brainlister.....

Answer 2

I think there is a mistake in first question , there should be +21 instead of -21 .

For answer see in the attachment .