Question

factorise
${x}^{2} - 14x + 45 = 0$
​

Answer 1

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Q:-factorise

${x}^{2} - 14x + 45 = 0$

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------>>>>Here is your answer<<<<--------

$⇒ {x}^{2} - 14x + 45 = 0$

$⇒ {x}^{2} - 9x - 5x + 45 = 0$

$⇒x(x - 9) - 5(x - 9)$

$⇒(x - 5)(x - 9)$

$⇒x = 5 \: and x = 9$

HOPE IT HELPS YOU..

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Thankyou:)

Answer 2

Answer:

please mark as brain list

Step-by-step explanation:

How do you factor

x

2

+

14

x

+

45

?

Algebra Factoring Completely

3 Answers

BRIAN M.

Mar 31, 2017

(

x

+

5

)

(

x

+

9

)

Explanation:

In order to the trinomial

x

2

+

14

x

+

45

Begin by finding the factors for the first term

x

2

=

x

⋅

x

Place those factors as the first term in each parenthesis

(

x

_

)

(

x

_

)

Since both signs of the trinomial are positive you will be adding the factors and both signs will be positive.

(

x

+

_

)

(

x

+

_

)

Now determine the factors of the third term

45

=

1

⋅

45

,

3

⋅

15

,

5

⋅

9

We need the factors that will add up to the middle term

14

=

5

+

9

Place these factors as the second term in each of the parenthesis.

(

x

+

5

)

(

x

+

9

)

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