Question

Factorise....

[tex] x^3 - 23x^2 + 142x - 120.

Answer 1

Answer:

Step-by-step explanation:

Hope it helps u

Answer 2

Answer:

$(x-1)(x-10)(x-12)$

Step-by-step explanation:

$x^{3} -23x^{2}+142x-120\\\\= x^{3}-x^{2}-22x^{2}+22x+120x-120\\\\=x^{2}(x-1)-22x(x-1)+120(x-1)\\\\=(x-1)(x^{2}-22x+120)\\\\=(x-1)(x^{2}-10x-12x+120)\\\\=(x-1)[x(x-10)-12(x-10)]\\\\=(x-1)(x-10)(x-12)$

So the factor of $x^{3} -23x^{2}+142x-120$ is $(x-1)(x-10)(x-12)$