Question

factorise the following​

Answer 1

Answer:

3(m^2+n)^2-7(m^2+n)+2

let m^2+n be x

3x^2-7x+2

3×^2-6×-×+2

3×(×-2)-1(×-2)

(×-2)(3×-1)

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Answer 2

Question:

Factorise the given expression ;

3(m^2 + n)^2 - 7(m^2 + n) + 2

Answer:

(m^2 + n - 2)(3m^2 + 3n - 1)

Solution:

We have;

=> 3(m^2 + n)^2 - 7(m^2 + n) + 2

=> 3(m^2 + n)^2 - 6(m^2 + n)

- (m^2 + n) + 2

=> 3(m^2 + n)(m^2 + n - 2)

- (m^2 + n - 2)

=> (m^2 + n - 2){3(m^2 + n) - 1}

=> (m^2 + n - 2)(3m^2 + 3n - 1)

Hence,

The factorised form of the given expression is ;

(m^2 + n - 2)(3m^2 + 3n - 1)