Question

Factorise the following
ax+by+bx+az+ay+ay+bz​

Answer 1

Answer

ax+by+bx+az+ay+bz

By rearrangement,

ax+ay+az+bx+by+bz

Taking a and b common

a(x+y+z)+b(x+y+z)

Taking x+y+z common

(x+y+z)(a+b)

Thus the expression is factorised.

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