Question

factorise the following using identities... 1)
${4y}^{2} - 4y + 1 \: dont \: send \: answer \: if \: u \: do \: not \: know$

Answer 1

Heya ✋

Let see your answer !!!!!
$4y ^{2} - 4y + 1 \\ = 4y ^{2} - 2y - 2y + 1 \\ = 2y(2y - 1) -1 (2y - 1) \\ = (2y - 1)(2y - 1)$
Thanks :))))

Answer 2

Hi Friend !!!

Here is ur answer !!!

4y²-4y +1

= (2y)²-2(2y)(1) + 1²

= (2y-1)²

= (2y-1)(2y-1)



Hope it helps u