Question

factorise this pls tomorrow is my exam

Answer 1

let p-q=A,

q-r=B,

r-p=C,

here

A+B+C=p-q+q-r+r-p,

A+B+C=0,

since A+B+C=0,

then

A³+B³+C³=3ABC,

therefore

(p-q)³ + (q-r)³ + (r-p)³,

3×(p-q)(q-r)(r-p)

Answer 2

Given:- (p-q)³+(q-r)³+(r-p)³ then,  Let, x=p-q y=q-r z=r-p Now,  Adding both the sides x+y+z=p-q+q-r+r-p x+y+z=0  We know that if x+y+z=0, then x³+y³+z³=3xyz ( It is an identity)   x³+y³+z³=3(p-q)(q-r)(r-p)  (p-q)³+(q-r)³+(r-p)³=3(p-q)(q-r)(r-p)    Be Brainly