Math, asked by yadavmishi95, 5 months ago

factorise using identity x²+10x+25​

Answers

Answered by Anonymous
4

Step-by-step explanation:

x {}^{2}  + 10x + 25 \\  {x}^{2}  + 5x + 5x + 25 \\ x(x + 5) + 5(x + 5) \\ (x + 5)(x + 5) \\ (x + 5) {}^{2}

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Answered by jssn012
1

x²+ 5x+5x+25=0

x(x+5)+5(x+5)=0

(x+5)(x+5)=0

x+5=0 , x+5=0

x=-5, x= -5

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