factorise(x+2)^2+p^2+2p(x+2)
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Answer:
(x + 2 + p)*(x + 2 + p)
Step-by-step explanation:
Hi,
Given expression is (x + 2)² + p² + 2p(x + 2),
which can be written as
(x + 2)² + 2p(x + 2) + p²
Splitting 2p(x + 2) into 2 parts, we get
= (x + 2)² + p(x + 2) + p(x + 2) + p²
Taking (x +2) common out from first 2 terms and
p common from last 2 terms, we get
= (x + 2)[(x + 2) + p] + p[(x + 2) + p]
Taking (x + 2 + p) as common, we get
= (x + 2 + p)*(x + 2 + p)
Hope, it helps !
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