Factorise: x^2+4y^2-z^2-4xy
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x^2+4y^2-z^2-4xy
(using a^2+b^2-2ab=(a-b)^2, factorise the expression. )
= (x-2y)^2 - z^2
(now, using a^2-b^2=(a-b)(a+b), factorise the expression)
= (x-2y-z)(x-2y+z)
(using a^2+b^2-2ab=(a-b)^2, factorise the expression. )
= (x-2y)^2 - z^2
(now, using a^2-b^2=(a-b)(a+b), factorise the expression)
= (x-2y-z)(x-2y+z)
Answered by
31
Answer:
Step-by-step explanation:
x^2+4y^2-z^2-4xy
=x^2+4y^2-4xy-z^2 ( change the position of -z^2)
=(we will observe that x^2+4y^2-4xy is a perfect square trinomial) factorise it....
=[(x-2y)^2] - (z^2)
= now group them
= (x-2y+z)(x-2y-z)
Please mark it as brainliest☺☺
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