factorise x^2+6√2x+10
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Answered by
1
Hey
x² + 6√2x + 10
=> x² + 5√2x + √2x + 10 = 0
=> x ( x + 5√2 ) + √2 ( x + 5√2 ) = 0
=> ( x + √2 ) ( x + 5√2 ) = 0
Now ,
if x + √2 = 0
=> x = - √2
And ,
if x + 5√2 = 0
=> x = -5√2
thanks :)
x² + 6√2x + 10
=> x² + 5√2x + √2x + 10 = 0
=> x ( x + 5√2 ) + √2 ( x + 5√2 ) = 0
=> ( x + √2 ) ( x + 5√2 ) = 0
Now ,
if x + √2 = 0
=> x = - √2
And ,
if x + 5√2 = 0
=> x = -5√2
thanks :)
Answered by
1
Hey!
Abhiranjan raj helping you.
x^2+6√2x+10
=x^2+1√2x+2√5x+10
=x(x+√2)+2√5(x+√2)
=(x+√2)(x+2√5)
Hope it helps you
Abhiranjan raj helping you.
x^2+6√2x+10
=x^2+1√2x+2√5x+10
=x(x+√2)+2√5(x+√2)
=(x+√2)(x+2√5)
Hope it helps you
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