Question

factorise: x^3 - 3x^2 + x + 2​

Answer 1

here comes a solution

Answer 2

Answer:

(x-2)(x^2-x-1)

Step-by-step explanation:

Apply rational root theorem

$(x-2)[tex]\frac{x^3-3x^2+x+2}{x-2}=x^2-x-1\\\\Divide \frac{x^3-3x^2+x+2}{x-2}\\\\x^2+\frac{-x^2+x+2}{x-2} \\=x^2-x+\frac{-x+2}{x-2}\\=\frac{-x+2}{x-2} = -1\\therefore x^2-x-1\\(x-2)(x^2-x-1)$