Factorise x cube - 3x square - 9x - 5
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The answer is in the attachment
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krazzy:
no the answer should be (x + 1 ) (x+1) (x - 5)
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15
x³ - 3x² - 9x - 5
= x³ - 5x² + 2x² - 10x + x - 5
= x²(x - 5) + 2x(x - 5) + 1(x - 5)
= (x - 5)(x² + 2x + 1)
= (x - 5)[x² + x + x + 1]
= (x - 5)[x(x + 1) + 1(x + 1)]
= (x - 5)(x + 1)(x + 1).
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