Question

factorise x cube minus one upon x cube

Answer 1

hi dear...✌✌✌✌



here is ur answer...☺☺



x³-1/x³✔✔
taking LCM

(x³-x³)/x³✔✔
→0/x³✔✔

→→0 is the answer✔✔



hope it helps✌✌
please mark it as brainliest☺☺



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Answer 2

$\underline{\bold{Solution:-}}$

${x}^{3} - \frac{1}{ {x}^{3} } \\ \\ = {x}^{3} - {( \frac{1}{x} )}^{3} \\ \\ \bold{It \: is \: in \: the \: form \: of \: {a}^{3} - {b}^{3} }\\ \\\bold{Using \: identity }\\ \\\bold{ {a}^{3} - {b}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} )} \\ \\ = (x - \frac{1}{x} )( {x}^{2} + x \times \frac{1}{x} + {( \frac{1}{x} )}^{2} ) \\ \\ \boxed{\bold{= (x - \frac{1}{x} )( {x}^{2} + 1 + \frac{1}{ {x}^{2} } )}}$

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