Question

factorise x square minus y square upon 100

Answer 1

${x}^{2} - \frac{ {y}^{2} }{100} \\ = (x + \frac{y}{10} )(x - \frac{y}{10} )$

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Answer 2

$x^2-\frac{y^2}{100}=(x-\frac{y}{10})(x+\frac{y}{10})$

Solution:

Given that,

We have to factorize:

$x^2-\frac{y^2}{100}$

We have to write as product of factors

From given,

$x^2-\frac{y^2}{100} \\\\Useing\ algebriac\ identity\ \\\\a^2-b^2=(a-b)(a+b)\\\\x^2-\frac{y^2}{100}\\\\a=x\text{ and }b=\frac{y}{10}\\\\x^2-\frac{y^2}{100}=(x-\frac{y}{10})(x+\frac{y}{10})$

Thus the given expression is factorized

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