Two years ago,Dilip was three times as old as his son and two years hence twice his age will be equal to five times that of his son.what is the present age of Dilip?????????
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Answered by
1
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3x+4 = 5(x+4)
3x+4 = 5x+20
3x-5x= 20-4
-2x = 16
-x = 16/2
-x= 8
x= -8
3x+4 = 5(x+4)
3x+4 = 5x+20
3x-5x= 20-4
-2x = 16
-x = 16/2
-x= 8
x= -8
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Answered by
117
Given :-
→ Let Dilip's son's age 2 years ago be x years.
Then, Dilip's age 2 years ago = ( 3x ) years
Thus , the son's age 2 years hence (x + 4) years.
Dilip's age 2 years hence (3x + 4) years.
→ 2 ( 3x + 4 ) = 5 ( x + 4 )
→ 6x + 8 = 5x +20
→ x = 12.
∴ Dilip's son's age 2 years ago = 12 years and Dilip's age 2 years ago = 36 years.
∴ son's present age = 14 years, and
Dilip's present age = 38 years.
Thank You!
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