Factorise x(x+1)(x-2)(x-3)-4
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Answer:
➪ x(x + 1) (x - 2) (x - 3) - 4
➪ x(x + 1) (x - 2) (x - 3) - 4
➭ (x² + x) (x - 2) (x - 3) - 4
➭ x²(x - 2) + x(x - 2) (x - 3) - 4
➭ (x³ - 2x² + x² - 2x) (x - 3) - 4
➭ (x³ - x² - 2x) (x - 3) - 4
➭ x(x³ - x² - 2x) - 3(x³ - x² - 2x) - 4
➭ x⁴ - x³ - 2x² - 3x³ + 3x² + 6x - 4
➭ x⁴ - x³ - 3x³ - 2x² + 3x² + 6x - 4
➭ x⁴ - 4x³ + x² + 6x - 4
∴ The answer of this question is
x⁴ - 4x³ + x² + 6x - 4
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