Math, asked by iuooooooooooo, 29 days ago

Solve for x and y 6/(x-1) - 3/(y-2) =1 5/(x-1) + 1/(y-2) =2

Answers

Answered by cjsdnjvmmmmmmmmmmmm
1

Answer:

x=4,y=5

hope it helps

Answered by DeeznutzUwU
2

   Answer:

   x = 4  ; y = 5

   Step-by-step explanation:

   The two given equations are:  \frac{6}{x-1} - \frac{3}{y-2} = 1    ---(1)

                                                       \frac{5}{x-1} +\frac{1}{y-2} = 2   ---(2)

   Let \frac{1}{x-1}  = a and \frac{1}{y-2}= b

(1) now becomes

   6a-3b = 1     ---(3)

(2) now becomes

   5a + b = 2       ---(4)

   From (4) we get

   b = 2-5a

   Substituting the value of b from (4) into (3)

6a -3(2-5a) = 1

6a - 6 + 15a = 1

21a = 7

a = \frac{1}{3}

   Substituting the value of a into (4)

5(\frac{1}{3} ) + b = 2

b = 2-\frac{5}{3}

b = \frac{6-5}{3}

b = \frac{1}{3}

   We know that \frac{1}{x-1}  = a and \frac{1}{y-2}= b

\frac{1}{x-1} = \frac{1}{3}     ; \frac{1}{y-2} = \frac{1}{3}

x-1 = 3   ; y-2 = 3

x = 4         ; y = 5

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