factorise: x2 - 5x - 6
Answers
Answered by
18
hey!
here is ur answer!
=======================
=> x^2 - 5x - 6 =0
( use the rule of middle term expansion)
=> x^2 - 6x + x - 6 =0
=> x ( x - 6 ) + 1( x - 6 ) = 0
=> (x+1) (x -6 ) = 0
hence the value of x ,
=> x +1 = 0
x = -1
=> x - 6 = 0
x = 6
x = -1 or 6
hope it helps!
here is ur answer!
=======================
=> x^2 - 5x - 6 =0
( use the rule of middle term expansion)
=> x^2 - 6x + x - 6 =0
=> x ( x - 6 ) + 1( x - 6 ) = 0
=> (x+1) (x -6 ) = 0
hence the value of x ,
=> x +1 = 0
x = -1
=> x - 6 = 0
x = 6
x = -1 or 6
hope it helps!
Answered by
9
HOLA MATE HERE IS YOUR ANSWER....
WE WILL SOLVE IT BY MIDDLE TERM SPLITTING
Sum = 5x
-6x + 1x = 5x
ANSWER :
NOW WE CAN FURTHER CONTINUE IT BY TAKING COMMON
SO,
x(x - 6) + 1 (x - 6)
Answer :
(X+1)(X-6)
PLEASE MARK AS BRAINLIEST
WE WILL SOLVE IT BY MIDDLE TERM SPLITTING
Sum = 5x
-6x + 1x = 5x
ANSWER :
NOW WE CAN FURTHER CONTINUE IT BY TAKING COMMON
SO,
x(x - 6) + 1 (x - 6)
Answer :
(X+1)(X-6)
PLEASE MARK AS BRAINLIEST
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