Question

factorise x² + ( p + 1/p ) x + 1
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Answer 1

Answer:

Let, p(x) = 2x3–9x2 + x + 12 Put, x = –1 in p(x) p(–1) = 2 × (–1)3–9 (–1)2 + (–1) + 12 ... + 6 1 = 1 – 2 – 5 + 6 = 0 Hence, (x–1) is a factor of p (x), then x3–2x2–5x + 6 = x2 ...