Question

factorise x³-3x²-9x-5​

Answer 1

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A polynomial is an algebraic expression in which the exponent on any variable is a whole number. Polynomial’s degree is the highest or the greatest power of a variable in a polynomial equation.

A polynomial can be written as the product of its factors having a degree less than or equal to the original polynomial.

The process of factoring is called factorization of polynomials.

Given that x³ – 3x² – 9x – 5

The equation can be simplified as

= x³ + x² – 4x² – 4x – 5x – 5

= x²(x + 1) – 4x (x + 1) – 5(x + 1)

= (x + 1)(x² – 4x – 5)

= (x + 1)(x² -5x + x – 5)

= (x + 1)(x – 5)(x + 1)

Hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .

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Answer 2

Step-by-step explanation:

Given that x³ – 3x² – 9x – 5

Given that x³ – 3x² – 9x – 5The equation can be simplified as

Given that x³ – 3x² – 9x – 5The equation can be simplified as= x³ + x² – 4x² – 4x – 5x – 5

Given that x³ – 3x² – 9x – 5The equation can be simplified as= x³ + x² – 4x² – 4x – 5x – 5= x²(x + 1) – 4x (x + 1) – 5(x + 1)

Given that x³ – 3x² – 9x – 5The equation can be simplified as= x³ + x² – 4x² – 4x – 5x – 5= x²(x + 1) – 4x (x + 1) – 5(x + 1)= (x + 1)(x² – 4x – 5)

Given that x³ – 3x² – 9x – 5The equation can be simplified as= x³ + x² – 4x² – 4x – 5x – 5= x²(x + 1) – 4x (x + 1) – 5(x + 1)= (x + 1)(x² – 4x – 5)= (x + 1)(x² -5x + x – 5)

Given that x³ – 3x² – 9x – 5The equation can be simplified as= x³ + x² – 4x² – 4x – 5x – 5= x²(x + 1) – 4x (x + 1) – 5(x + 1)= (x + 1)(x² – 4x – 5)= (x + 1)(x² -5x + x – 5)= (x + 1)(x – 5)(x + 1)

Given that x³ – 3x² – 9x – 5The equation can be simplified as= x³ + x² – 4x² – 4x – 5x – 5= x²(x + 1) – 4x (x + 1) – 5(x + 1)= (x + 1)(x² – 4x – 5)= (x + 1)(x² -5x + x – 5)= (x + 1)(x – 5)(x + 1)Hence, (x +1), (x -5) and (x +1) are the factors of given polynomial .